### NEET Solved Paper 2018 Question 1

##### Question: The volume (V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is

#### Options:

A) $ \frac{1}{3} $

B) $ \frac{2}{3} $

C) $ \frac{2}{5} $

D) $ \frac{2}{7} $

## Show Answer

#### Answer:

Correct Answer: C

#### Solution:

- Given process is isobaric $ \text{dQ=n}{C_p}dT $ $ \text{dQ=n}( \frac{5}{2}R )dT $ $ \text{dW=PdV=nRdT} $

Required ratio $ \text{=}\frac{dW}{dQ}\text{=}\frac{nRdT}{n( \frac{5}{2}R )dT}\text{=}\frac{2}{5} $