### NEET Solved Paper 2016 Question 11

##### Question: A refrigerator works between $ 4{{,}^{o}}C $ and $ 30{{,}^{o}}C. $ It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is: (Take 1 cal = 4.2 Joules)

#### Options:

A) 2.365 W

B) 23.65 W

C) 236.5 W

D) 2365 W

## Show Answer

#### Answer:

Correct Answer: C

#### Solution:

- $ \beta =\frac{Q _2}{W}=\frac{T _2}{T _1-T _2} $ (Where $ Q _2 $ is heat removed)

$ \Rightarrow $ $ \frac{600\times 4.2}{W}=\frac{277}{303-277} $

$ \Rightarrow $ $ W=236.5,joule $

$ \Rightarrow $ $ Power=\frac{W}{t}=\frac{236.5,joule}{1,\sec }=236.5watt. $