### Laws Of Motion Question 4

#### Question 4 - 2024 (27 Jan Shift 1)

A train is moving with a speed of $12 m / s$ on rails which are $1.5 m$ apart. To negotiate a curve radius $400 m$, the height by which the outer rail should be raised with respect to the inner rail is (Given, $g=10 m / s^{2}$ ):

(1) $6.0 cm$

(2) $5.4 cm$

(3) $4.8 cm$

(4) $4.2 cm$

## Show Answer

#### Answer: (2)

#### Solution:

$\tan \theta=\frac{v^{2}}{Rg}=\frac{12 \times 12}{10 \times 400}$

$\tan \theta=\frac{h}{1.5}$

$\Rightarrow \frac{h}{1.5}=\frac{144}{4000}$

$h=5.4 cm$