In alkaline medium. $MnO _4^{-}$ oxidises $I^{-}$ to
(1) $IO _4^{-}$
(2) $IO^{-}$
(3) $I _2$
(4) $IO _3^{-}$
$2 MnO _4^{-}+H _2 O+I^{-} \xrightarrow{\text { alkaline medium }} 2 MnO _2+2 OH^{-}+IO _3^{-}$
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