D And F Block Elements Question 18
Question 18 - 2024 (31 Jan Shift 1)
The ‘Spin only’ Magnetic moment for $\left[Ni\left(NH _3\right) _6\right]^{2+}$ is _______ $\quad \times 10^{-1} BM$.
$($ given $=$ Atomic number of $Ni: 28)$
Show Answer
Answer (28)
Solution
$NH _3$ act as WFL with $Ni^{2+}$
$Ni^{2+}=3 d^{8}$
No. of unpaired electron $=2$
$$ \begin{aligned} \mu=\sqrt{n(n+2)} & =\sqrt{8}=2.82 BM \\ & =28.2 \times 10^{-1} BM \\ \text { x } & =28 \end{aligned} $$
