Chemical Bonding And Molecular Structure Question 2
Question 2 - 2024 (01 Feb Shift 1)
Arrange the bonds in order of increasing ionic character in the molecules. $LiF, K _2 O, N _2, SO _2$ and $CIF _3$.
(1) $CIF _3<N _2<SO _2<K _2 O<LiF$
(2) $LiF<K _2 O<CIF _3<SO _2<N _2$
(3) $N _2<SO _2<CIF _3<K _2 O<LiF$
(4) $N _2<CIF _3<SO _2<K _2 O<LiF$
Show Answer
Answer (3)
Solution
Increasing order of ionic character $N _2<SO _2<ClF _3<K _2 O<LiF$
Ionic character depends upon difference of electronegativity (bond polarity).
