### Magnetic Effects Of Current Question 23

#### Question 23 - 01 February - Shift 2

A square shaped coil of area $70 cm^{2}$ having 600 turns rotates in a magnetic field of $0.4 wbm^{-2}$, about an axis which is parallel to one of the side of the coil and perpendicular to the direction of field. If the coil completes 500 revolution in a minute, the instantaneous emf when the plane of the coil is inclined at $60^{\circ}$ with the field, will be $V$. (Take $\pi=\frac{22}{7}$ )

## Show Answer

#### Answer: (44)

#### Solution:

#### Formula: Magnetic field due to a straight wire

$N=600, A=70 \times 10^{-4} m^{2}, B=0.4 T$

$\omega=\frac{500 \times 2 \pi}{60}=\frac{100 \pi}{6} rad / s$

$E=NAB \omega \sin \omega t$ is angle $b / w \overrightarrow{{}A} ~\&~ \overrightarrow{{}B}$

$=600 \times 70 \times 10^{-4} \times 0.4 \times \frac{100 \pi}{6} \times \frac{1}{2}$

$=44 V$