### Gravitation Question 9

#### Question 9 - 29 January - Shift 1

Two particles of equal mass ’ $m$ ’ move in a circle of radius ’ $r$ ’ under the action of their mutual

gravitational attraction. The speed of each particle will be :

(1) $\sqrt{\frac{GM}{2 r}}$

(2) $\sqrt{\frac{4 GM}{r}}$

(3) $\sqrt{\frac{GM}{r}}$

(4) $\sqrt{\frac{GM}{4 r}}$

## Show Answer

#### Answer: (4)

#### Solution:

#### Formula: Universal Law of Gravitation, Centripetal Force

$\frac{G m^{2}}{4 r^{2}}=\frac{m v^{2}}{r}$