Coordination Compounds Question 2
Question 2  24 January  Shift 1
The delectronic configuration of $[CoCl_4]^{2}$ in tetrahedral crystal field is $e^{m} t_2{ }^{n}$. Sum of ’ $m$ ’ and ’number of unpaired electrons is
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Answer: (7)
Solution:
Formula: Number of unpaired electron in vcoordination number four
$Co^{2+}: 3 d^{7} 4 s^{0}, Cl^{}:$WFL
$111 t_2$

 $e$
Configuration $e^{4} t_2{ }^{3}: m=4$
Number of unpaired electrons $=3$
So, answer $=7$