### JEE Main Solved Paper 2017 Question 6

##### Question: A diverging lens with magnitude of focal length 25 cm is placed at a distance of 15 cm from a converging lens of magnitude of focal length 20 cm. A beam of parallel light falls on the diverging lens. The final image formed is: [JEE Main Solved Paper-2017]

#### Options:

A) real and at a distance of 40 cm from the divergent lens

B) real and at a distance of 6 cm from the convergent lens

C) real and at a distance of 40 cm from convergent lens

D) virtual and at a distance of 40 cm from convergent lens. [JEE Main 2017]

## Show Answer

#### Answer:

Correct Answer: C

#### Solution:

- As parallel beam incident on diverging lens if forms virtual image at $ v _1=-25,cm $ from the diverging lense which works as a object for the converging lense (f = 20 cm) So for converging lens $ u=-40cm,f=20,cm $

$ \therefore $ Finance image $ \frac{1}{V}-\frac{1}{-40}=\frac{1}{20} $ V = 40 cm from converging lenses.