### JEE Main On 8 April 2017 Question 14

##### Question: There is a uniform electrostatic field in a region. The potential at various points on a small sphere centred at P, in the region, is found to vary between in limits 589.0V to 589.8 V. What is the potential at a point on the sphere whose radius vector makes an angle of $ 60{}^\circ $ with the direction of the field? [JEE Online 08-04-2017]

#### Options:

A) 589.4 V

B) 589.5 V

C) 589.2 V

D) 589.6 V

## Show Answer

#### Answer:

Correct Answer: A

#### Solution:

- $ \Delta V=E.d $ 0.8 = Ed (max) $ \Delta V=Ed\cos \theta =0.8\times \cos 60 $ = 0.4 +589.0 =589.4