NEET Solved Paper 2019 Question 8
Question: A 800 turn coil of effective area $ 0.05m^{2} $ is kept perpendicular to a magnetic field $ 5\times 10^{5}T $ . When the plane of the coil is rotated by 90º around any of its coplanar axis in 0.1 s, the emf induced in the coil will be: [NEET 5-5-2019]
Options:
A) $ 2\times 10^{3}V $
B) 0.02 V
C) 2 V
D) 0.2 V
Show Answer
Answer:
Correct Answer: B
Solution:
- $ emf=\frac{\Delta \phi }{\Delta t}=\frac{BAN}{\Delta t} $ $ =\frac{(5\times 10^{5})(0.05)(8000)}{0.1} $ $ =\frac{200\times {10^{-5}}\times {10^{-2}}\times 10^{2}}{{10^{-1}}}=0.02,volt $
