NEET Solved Paper 2019 Question 43
Question: Two point charges A and B, having charges +Q and -Q respectively, are placed at certain distance apart and force acting between them is F. If 25 % charge of A is transferred to B, then force between the charges becomes- [NEET 5-5-2019]
Options:
A) $ \frac{16F}{9} $
B) $ \frac{4F}{3} $
C) F
D) $ \frac{9F}{16} $
Show Answer
Answer:
Correct Answer: D
Solution:
- $ F=\frac{KQQ}{r^{2}} $ $ F’=\frac{K\frac{3Q}{4}\times \frac{3Q}{4}}{r^{2}}=\frac{9F}{16} $
