NEET Solved Paper 2019 Question 27
Question: A soap bubble, having radius of 1 mm, is blown from a detergent solution having a surface tension of $ 2.5\times 10^{2} $ N/m. The pressure inside the bubble equals at a point $ Z _0 $ below the free surface of water in a container. Taking $ g=10m/s^{2} $ , density of water $ =10^{3}kg/m^{3} $ , the value of $ Z _0 $ is: [NEET 5-5-2019]
Options:
A) 1 cm
B) 0.5 cm
C) 100 cm
D) 10 cm
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \rho gZ _0=\frac{4T}{R} $ $ 10^{3}.10.Z _0=\frac{4(2.5\times {10^{-2}})}{{10^{-3}}} $ $ =\frac{100}{10^{4}} $ $ Z _0={10^{-2}} $ $ Z=1cm $
