NEET Solved Paper 2018 Question 32
Question: A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will be [NEET - 2018]
Options:
A) 0.8
B) 0.25
C) 0.5
D) 0.4
Show Answer
Answer:
Correct Answer: B
Solution:
- According to law of conservation of linear momentum, $ mv+4m\times 0=4mv’+0 $ $ v’=\frac{v}{4} $ $ e=\frac{\text{Relative velocity of separation}}{\text{Relative velocity of approach}}=\frac{\frac{v}{4}}{v} $ $ e=\frac{1}{4}=0.25 $
