NEET Solved Paper 2018 Question 28
Question: An inductor 20 mH, a capacitor $ 100\mu F $ and a resistor $ 50\Omega $ are connected in series across a source of emf, V=10 sin 314 t. The power loss in the circuit is [NEET - 2018]
Options:
A) 2.74 W
B) 0.43 W
C) 0.79 W
D) 1.13 W
Show Answer
Answer:
Correct Answer: C
Solution:
- $ {P _{av}}\text{=}{{( \frac{{V _{RMS}}}{Z} )}^{2}}R $ $ \text{Z=}\sqrt{R^{2}+{{( \omega L-\frac{1}{\omega C} )}^{2}}}=56\Omega $
$ \therefore P _{av}={{( \frac{10}{( \sqrt{2} )56} )}^{2}}\times 50=0.79W $
