NEET Solved Paper 2018 Question 25
Question: A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $ 20m/s^{2} $ at a distance of 5 m from the mean position. The time period of oscillation is [NEET - 2018]
Options:
A) $ 2s $
B) $ \pi s $
C) $ 2\pi s $
D) $ 1s $
Show Answer
Answer:
Correct Answer: B
Solution:
- $ | a |={{\omega }^{2}}y $
$ \Rightarrow 20={{\omega }^{2}}(5) $
$ \Rightarrow \omega =2rad/s $ $ T=\frac{2\pi }{\omega }=\frac{2\pi }{2}=\pi s $
