NEET Solved Paper 2018 Question 25

Question: A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $ 20m/s^{2} $ at a distance of 5 m from the mean position. The time period of oscillation is [NEET - 2018]

Options:

A) $ 2s $

B) $ \pi s $

C) $ 2\pi s $

D) $ 1s $

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ | a |={{\omega }^{2}}y $
    $ \Rightarrow 20={{\omega }^{2}}(5) $
    $ \Rightarrow \omega =2rad/s $ $ T=\frac{2\pi }{\omega }=\frac{2\pi }{2}=\pi s $