NEET Solved Paper 2016 Question 13
Question: Consider the junction diode as ideal. The value of current flowing through AB is :
Options:
A) $ 0,A $
B) $ {10^{-2}}A $
C) $ {10^{-1}}A $
D) $ {10^{-3}}A $
Show Answer
Answer:
Correct Answer: B
Solution:
- Since diode is in forward bias $ i=\frac{\Delta V}{R}=\frac{4-(-6)}{1\times 10^{3}}=\frac{10}{10^{3}}={10^{-2}}A $
