NEET Solved Paper 2016 Question 28
Question: Match the compounds given in column I with the hybridisation and shape given in column II and mark the correct option.
Column-I | Column -II |
---|---|
(A) $ XeF _6 $ | (i) Distorted octahedral |
(B) $ XeO _3 $ | (ii) Square planar |
(C) $ XeOF _4 $ | (iii) Pyramidal |
(D) $ XeF _4 $ | (iv) Square pyramidal |
Options:
A) (A)-(i) (B)-(iii) (C)- (iv) (D)-(ii)
B) (A)-(i) (B)-(ii) (C)- (iv) (D)-(iii)
C) (A)-(iv) (B)-(iii) (C)- (i) (D)-(ii)
D) (A)-(iv) (B)-(i) (C)- (ii) (D)-(iii)
Show Answer
Answer:
Correct Answer: A
Solution:
- In $XeF_6$, the central Xe atom undergoes $sp^3d^3$ hybridisation and the molecular geometry is distorted octahedral with 1 lone pair and 6 bond pairs of electrons.