Neet Solved Paper 2015 Question 4
Question: Three blocks A, B and C of masses 4 kg, 2 kg and 1 kg respectively, are in contact on a 1 frictionless surface, as shown. If a force of 14 N is applied on the 4 kg block, then the contact force between A and B is
_img/neet_solved_paper_2015_c_question_4_.png)
Options:
A) 2N
B) 6N
C) 8 N
D) 18 N
Show Answer
Answer:
Correct Answer: B
Solution:
- Given, $ m _{A}=4kg $ So total mass (M) = $ 4+2+1=7kg $
Now, $ F=Ma\Rightarrow 14=7a\Rightarrow a=2m/s^{2} $
FED of block A, $ F=F’=4a\Rightarrow F’=14-4\times 2\Rightarrow F’=6N $
