Neet Solved Paper 2015 Question 39
Question: The enolic form of ethyl acetoacetate as below has
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Options:
A) 18 sigma bonds and 2 pi-bonds
B) 16 sigma bonds and 1 pi-bond
C) 9 sigma bonds and 2 pi-bonds
D) 9 sigma bonds and 1 pi-bond
Show Answer
Answer:
Correct Answer: A
Solution:
- The enolic form of ethyl acetoacetate has 16 single bonds i.e. 16 $ \sigma $ -bonds and 2 double bonds i.e. 2 $ \sigma $ -bonds and 2 $ \pi $ -bonds. Hence, the given structure has 18 $ \sigma $ -bonds and 2 $ \pi $ -bonds.
