NEET Solved Paper 2014 Question 44
Question: Identity Z in the sequence of reactions, [AIPMT 2014] $ CH _3CH _2CH=CH _2\xrightarrow{HBr/H _2O _2}Y $ $ \xrightarrow{C _2H _5ONa}Z $
Options:
A) $ CH _3-{{(CH _2)}_3}-O-CH _2CH _3 $
B) $ {{(CH _3)}_2}CH _2-O-CH _2CH _3 $
C) $ CH _3{{(CH _2)}_4}-O-CH _3 $
D) $ CH _3CH _2-CH(CH _3)-O-CH _2CH _3 $
Show Answer
Answer:
Correct Answer: A
Solution:
- $ CH _3CH _2CH=CH _2\xrightarrow[Anti,\text{-},\text{Markownikoff }’\text{ s}rule]{\text{HBr/}{H_2}{O_2}}CH _3CH _2CH _2CH _2Br $ $ CH _3CH _2CH _2CH _2Br\xrightarrow[S _{N}2reaction]{C _2H _5ONa}CH _3CH _2CH _2CH _2OC _2H _5 $
