Work Energy and Power - Result Question 25

28. A rubber ball is dropped from a height of $5 m$ on a plane, where the acceleration due to gravity is not shown. On bouncing it rises to $1.8 m$. The ball loses its velocity on bouncing by a factor of

[1998]

(a) $\frac{16}{25}$

(b) $\frac{2}{5}$

(c) $\frac{3}{5}$

(d) $\frac{9}{25}$

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Answer:

Correct Answer: 28. (b)

Solution:

  1. (b) According to principle of conservation of energy,

Loss in potential energy $=$ Gain in kinetic energy

$\Rightarrow m g h=\frac{1}{2} m v^{2} \Rightarrow v=\sqrt{2 g h}$

If $h_1$ and $h_2$ are initial and final heights, then $v_1=\sqrt{2 g h_1}$ and $v_2=\sqrt{2 g h_2}$ Loss in velocity,

$\Delta v=v_1-v_2=\sqrt{2 g h_1}-\sqrt{2 g h_2}$

$\therefore$ Fractional loss in velocity,

$=\frac{\Delta v}{v_1}=\frac{\sqrt{2 g h_1}-\sqrt{2 g h_2}}{\sqrt{2 g h_1}}=1-\sqrt{\frac{h_2}{h_1}}$

$=1-\sqrt{\frac{1.8}{5}}=1-\sqrt{0.36}=1-0.6=0.4=\frac{2}{5}$