Wave Optics - Result Question 34
37. In a Fresnel biprism experiment, the two positions of lens give separation between the slits as 16 $cm$ and $9 cm$ respectively. What is the actual distance of separation?
[1996]
(a) $12.5 cm$
(b) $12 cm$
(c) $13 cm$
(d) $14 cm$
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Answer:
Correct Answer: 37. (b)
Solution:
- (b) Separation between slits are $(r_1=) 16 cm$ and $(r_2=) 9 cm$.
Actual distance of separation $=\sqrt{r_1 r_2}$
$=\sqrt{16 \times 9}=12 cm$
