Thermodynamics - Result Question 16
17. A thermodynamic system undergoes cyclic process $A B C D A$ as shown in fig. The work done by the system in the cycle is :
[2014]
(a) $P_0 V_0$
(b) $2 P_0 V_0$
(c) $\frac{P_0 V_0}{2}$
(d) Zero
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Answer:
Correct Answer: 17. (d)
Solution:
- (d) Work done by the system in the cycle $=$ Area under $P-V$ curve and $V$-axis
$=\frac{1}{2}(2 P_0-P_0)(2 V_0-V_0)+$
$[-(\frac{1}{2})(3 P_0-2 P_0)(2 V_0-V_0)]$ $=\frac{P_0 V_0}{2}-\frac{P_0 V_0}{2}=0$
