System of Particles and Rotational Motion - Result Question 64

71. The moment of inertia of a disc of mass $M$ and radius $R$ about an axis, which is tangential to the circumference of the disc and parallel to its diameter, is

[1999]

(a) $\frac{3}{2} M R^{2}$

(b) $\frac{2}{3} M R^{2}$

(c) $\frac{5}{4} M R^{2}$

(d) $\frac{4}{5} M R^{2}$

Show Answer

Answer:

Correct Answer: 71. (c)

Solution:

  1. (c) Moment of inertia of disc about its diameter is $I_d=\frac{1}{4} M R^{2}$

MI of disc about a tangent passing through rim and in the plane of disc is

$I=I_d+M R^{2}=\frac{1}{4} M R^{2}+M R^{2}=\frac{5}{4} M R^{2}$