Ray Optics and Optical Instruments - Result Question 63
66. Angle of deviation ( $\delta$ ) by a prism (refractive index $=\mu$ and supposing the angle of prism A to be small) can be given by
[1994]
(a) $\delta=(\mu-1) A$ $\sin \frac{A+\delta}{2}$
(b) $\delta=(\mu+1) A$
(c) $\delta=\frac{2}{\sin \frac{A}{2}}$
(d) $\delta=\frac{\mu-1}{\mu+1} A$
Topic 5: Optical Instruments
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Answer:
Correct Answer: 66. (a)
Solution:
- (a) When the angle of prism is small, $\delta=(\mu-1) A$
