Physical World Units and Measurements - Result Question 15
15. If the dimensions of a physical quantity are given by $M^{a} L^{b} T^{c}$, then the physical quantity will be:
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(a) Velocity if $a=1, b=0, c=-1$
(b) Acceleration if $a=1, b=1, c=-2$
(c) Force if $a=0, b=-1, c=-2$
(d) Pressure if $a=1, b=-1, c=-2$
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Answer:
Correct Answer: 15. (d)
Solution:
- (d) Pressure $=\frac{\text{ Force }}{\text{ Area }}$
$\Rightarrow \frac{[MLT^{-2}]}{[L^{2}]}=[ML^{-1} T^{-2}]$
$\Rightarrow a=1, b=-1, c=-2$.
