Oscillations - Result Question 9
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12. Two particles are oscillating along two close parallel straight lines side by side, with the same frequency and amplitudes. They pass each other, moving in opposite directions when their displacement is half of the amplitude. The mean positions of the two particles lie on a straight line perpendicular to the paths of the two particles. The phase difference is
======= ####12. Two particles are oscillating along two close parallel straight lines side by side, with the same frequency and amplitudes. They pass each other, moving in opposite directions when their displacement is half of the amplitude. The mean positions of the two particles lie on a straight line perpendicular to the paths of the two particles. The phase difference is
3e0f7ab6f6a50373c3f2dbda6ca2533482a77bed:content/english/neet-pyq-chapterwise/physics/oscillations/oscillations—result-question-9.md (a) 0
(b) $2 \pi / 3$
(c) $\pi$
(d) $\pi / 6$
[2011M]
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Answer:
Correct Answer: 12. (b)
Solution:
- (b) Equation of SHM is given by $x=A \sin (\omega t+\delta)$
$(\omega t+\delta)$ is called phase.
When $x=\frac{A}{2}$, then $\sin (\omega t+\delta)=\frac{1}{2}$
$\Rightarrow \omega t+\delta=\frac{\pi}{6}$
or $\phi_1=\frac{\pi}{6}$
For second particle,
$\phi_2=\pi-\frac{\pi}{6}=\frac{5 \pi}{6}$
$\therefore \phi=\phi_2-\phi_1$
$=\frac{4 \pi}{6}=\frac{2 \pi}{3}$
