Oscillations - Result Question 59

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64. A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration a, then the time period is given by $T=2 \pi \sqrt{(l / g)}$, where $g$ is equal to

======= ####64. A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration a, then the time period is given by $T=2 \pi \sqrt{(l / g)}$, where $g$ is equal to

3e0f7ab6f6a50373c3f2dbda6ca2533482a77bed:content/english/neet-pyq-chapterwise/physics/oscillations/oscillations—result-question-59.md (a) $g$

(b) $g-a$

(c) $g+a$

(d) $\sqrt{(g^{2}+a^{2})}$

[1991]

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Solution:

  1. (d) The effective value of acceleration due to gravity is $\sqrt{(a^{2}+g^{2})}$

If a simple pendulum is suspended from a trolley that is moving with constant speed $v$ around $a$

$ \text{ circle of radius } r T=2 \pi \sqrt{\frac{l}{g^{2}+(\frac{v^{2}}{r})^{2}}} $