Laws of Motion - Result Question 64
64. A particle of mass $M$ is moving in a horizontal circle of radius $R$ with uniform speed $V$. When it moves from one point to a diametrically opposite point, its
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(a) kinetic energy changes by $M V^{2} / 4$
(b) momentum does not change
(c) momentum changes by $2 MV$
(d) kinetic energy changes by $M V^{2}$
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Answer:
Correct Answer: 64. (c)
Solution:
- (c) On the diametrically opposite points, the velocities have same magnitude but opposite directions. Therefore, change in momentum is $MV-(-MV)=2 MV$
