Electrostatic Potential and Capacitance - Result Question 34
36. Two condensers, one of capacity $C$ and other of capacity $C / 2$ are connected to a V-volt battery, as shown.
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The work done in charging fully both the condensers is
[2007]
(a) $\frac{1}{4} C V^{2}$
(b) $\frac{3}{4} C V^{2}$
(c) $\frac{1}{2} C V^{2}$
(d) $2 CV^{2}$.
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Answer:
Correct Answer: 36. (b)
Solution:
- (b) Work done $=$ Change in energy
$=\frac{1}{2}(C+\frac{C}{2}) V^{2}=\frac{1}{2}(\frac{3 C}{2}) V^{2}=\frac{3 C V^{2}}{4}$
