Dual Nature of Radiation and Matter - Result Question 29
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31. A source of light is placed at a distance of $50 cm$ from a photocell and the stopping potential is found to be $V_0$. If the distance between the light source and photocell is made $25 cm$, the new stopping potential will be [NEET Kar. 2013]
======= ####31. A source of light is placed at a distance of $50 cm$ from a photocell and the stopping potential is found to be $V_0$. If the distance between the light source and photocell is made $25 cm$, the new stopping potential will be [NEET Kar. 2013]
3e0f7ab6f6a50373c3f2dbda6ca2533482a77bed:content/english/neet-pyq-chapterwise/physics/dual-nature-of-radiation-and-matter/dual-nature-of-radiation-and-matter—result-question-29.md (a) $2 V_0$
(b) $V_0 / 2$
(c) $V_0$
(d) $4 V_0$
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Answer:
Correct Answer: 31. (c)
Solution:
- (c) Since, stopping potential is independent of distance hence new stopping potential will remain unchanged i.e., new stopping potential $=V_0$.
