Current Electricity - Result Question 4
5. A carbon resistor of $(47 \pm 4.7) k \Omega$ is to be marked with rings of different colours for its identification. The colour code sequence will be
[2018]
(a) Violet-Yellow-Orange-Silver
(b) Yellow-Violet-Orange-Silver
(c) Green-Orange-Violet-Gold
(d) Yellow-Green-Violet-Gold
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Answer:
Correct Answer: 5. (b)
Solution:
- (b) Colour code for carbon resistor
0 Black
1 Brown Tolerance: $\pm 5 %$ Gold
2 Red $\pm 10 %$ Silver
3 Orange $\pm 20 %$ No colour
4 Yellow
5 Green
6 Blue
7 Violet
8 Grey
9 White
$(47 \pm 4.7) k \Omega=47 \times 10^{3} \pm 10 %$
$\therefore$ Yellow - Violet - Orange - Silver
