Some Basic Concepts of Chemistry 2 Question 8
8. In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of $\mathrm{CO}_{2}$ is
(2019 Main, 10 Jan II)
(a) 2
(b) 5
(c) 1
(d) 10
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Solution:
- Reaction of oxalate with permanganate in acidic medium.
$$ \begin{array}{lccc} & 5 \mathrm{C}{2} \mathrm{O}{4}^{2-}+2 \mathrm{MnO}{4}^{-} \longrightarrow 10 \mathrm{CO}{2}+2 \mathrm{Mn}^{2+}+8 \mathrm{H}_{2} \mathrm{O} \ n \text {-factor : } & (4-3) \times 2=2 & (7-2)=5 & \ \text { Number of mole } & 5 & 2 & 10 \end{array} $$
$\Rightarrow 5 \mathrm{C}{2} \mathrm{O}{4}^{2-}$ ions transfer $10 e^{-}$to produce 10 molecules of $\mathrm{CO}_{2}$.
So, number of electrons involved in producing 10 molecules of $\mathrm{CO}{2}$ is 10 . Thus, number of electrons involved in producing 1 molecule of $\mathrm{CO}{2}$ is 1 .
