Some Basic Concepts of Chemistry 2 Question 33
33. How many millilitres of $0.5 \mathrm{M} \mathrm{H}{2} \mathrm{SO}{4}$ are needed to dissolve $0.5 \mathrm{~g}$ of copper (II) carbonate?
(1999, 3M)
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Solution:
- The balanced chemical reaction is
$$ \begin{array}{rlrl} & \mathrm{CuCO}{3}+\mathrm{H}{2} \mathrm{SO}{4} \longrightarrow \mathrm{CuSO}{4}+\mathrm{H}{2} \mathrm{O}+\mathrm{CO}{2} \ \text { millimol of } \mathrm{CuCO}{3} & =\frac{0.5 \times 1000}{123.5}=4.048 \ \Rightarrow & \text { Millimol of } \mathrm{H}{2} \mathrm{SO}_{4} \text { required } & =4.048 \ \because & \text { Millimol } & =\text { Molarity } \times \text { Volume (in mL) } \ \Rightarrow & \text { Volume } & =\frac{4.048}{0.50}=8.096 \mathrm{~mL} \end{array} $$
