Some Basic Concepts of Chemistry 2 Question 31
31. Calculate the amount of calcium oxide required when it reacts with $852 \mathrm{~g}$ of $\mathrm{P}{4} \mathrm{O}{10}$.
(2005, 2M)
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Solution:
- The balanced reaction is
$$ \begin{array}{l}6 \mathrm{CaO}+\mathrm{P}{4} \mathrm{O}{10} \longrightarrow 2 \mathrm{Ca}{3}\left(\mathrm{PO}{4}\right){2} \ \text { Moles of } \mathrm{P}{4} \mathrm{O}_{10}=\frac{852}{284}=3\end{array} $$
Moles of $\mathrm{CaO}$ required $=3 \times 6=18$ Mass of $\mathrm{CaO}$ required $=18 \times 56=1008 \mathrm{~g}$
