Some Basic Concepts of Chemistry 2 Question 28
28. The difference in the oxidation numbers of the two types of sulphur atoms in $\mathrm{Na}{2} \mathrm{~S}{4} \mathrm{O}_{6}$ is
(2011)
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Solution:
- $\mathrm{Na}{2} \mathrm{~S}{4} \mathrm{O}{6}$ is a salt of $\mathrm{H}{2} \mathrm{~S}{4} \mathrm{O}{6}$ which has the following structure
$\Rightarrow$ Difference in oxidation number of two types of sulphur $=5$
