Some Basic Concepts of Chemistry 2 Question 22
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22. The oxidation number of phosphorus in $\mathrm{Ba}\left(\mathrm{H}{2} \mathrm{PO}{2}\right)_{2}$ is
======= ####22. The oxidation number of phosphorus in $\mathrm{Ba}\left(\mathrm{H}{2} \mathrm{PO}{2}\right)_{2}$ is
3e0f7ab6f6a50373c3f2dbda6ca2533482a77bed (a) +3
(b) +2
(c) +1
(d) -1
(1988)
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Solution:
- In $\mathrm{Ba}\left(\mathrm{H}{2} \mathrm{PO}{2}\right)_{2}$, oxidation number of $\mathrm{Ba}$ is +2 . Therefore,
$$ \mathrm{H}{2} \mathrm{PO}{2}^{-}: 2 \times(+1)+x+2 \times(-2)=-1 $$
$$ \Rightarrow \quad x=+1 $$
