Some Basic Concepts of Chemistry 1 Question 8
8. The volume strength of $1 \mathrm{M} \mathrm{H}{2} \mathrm{O}{2}$ is
(Molar mass of $\mathrm{H}{2} \mathrm{O}{2}=34 \mathrm{~g} \mathrm{~mol}^{-1}$ )
(2019 Main, 12 Jan II)
(a) 16.8
(b) 22.4
(c) 11.35
(d) 5.6
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Solution:
- Concentration of $\mathrm{H}{2} \mathrm{O}{2}$ is expressed in terms of volume strength, i.e. “volume of $\mathrm{O}{2}$ liberated by $\mathrm{H}{2} \mathrm{O}_{2}$ at NTP”. Molarity is connected to volume strength as:
Molarity $(M)=\frac{x}{11.2}$ or $x=$ Molarity $\times 11.2$
where, $x=$ volume strength
So, for $1 \mathrm{M} \mathrm{H}{2} \mathrm{O}{2}, x=1 \times 11.2=11.2$
Among the given options, 11.35 is nearest to 11.2.
