Some Basic Concepts of Chemistry 1 Question 24
45. Find the molarity of water. Given: $\rho=1000 \mathrm{~kg} / \mathrm{m}^{3}$
(2003)
Show Answer
Solution:
- Mass of $1.0 \mathrm{~L}$ water $=1000 \mathrm{~g}$
$\Rightarrow \quad$ Molarity $=\frac{1000}{18}=55.56 \mathrm{~mol} \mathrm{~L}^{-1}$
