pBlock ElementsII 2 Question 5
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5. The type of hybridisation and number of lone pair(s) of electrons of $\mathrm{Xe}$ in $\mathrm{XeOF}_{4}$, respectively, are
======= ####5. The type of hybridisation and number of lone pair(s) of electrons of $\mathrm{Xe}$ in $\mathrm{XeOF}_{4}$, respectively, are
3e0f7ab6f6a50373c3f2dbda6ca2533482a77bed (a) $s p^{3} d^{2}$ and 1
(b) $s p^{3} d$ and 2
(c) $s p^{3} d$ and 1
(d) $s p^{3} d^{2}$ and 2
(2019 Main, 10 Jan I)
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Solution:
- In $\mathrm{XeOF}_{4}, \mathrm{Xe}$ is $s p^{3} d^{2}$-hybridised. Geometry of the molecule is octahedral, but shape of the molecule is square pyramidal.
According to VSEPR, theory it has one $\pi$ bond. Remaining six electron pairs form an octahedron with one position occupied by a lone pair.
Here, Xe contains one lone pair of electrons.
