pBlock ElementsII 2 Question 21
21. $\mathrm{HBr}$ and $\mathrm{HI}$ reduce sulphuric acid, $\mathrm{HCl}$ can reduce $\mathrm{KMnO}_{4}$ and $\mathrm{HF}$ can reduce
(1981, 1M)
(a) $\mathrm{H}{2} \mathrm{SO}{4}$
(b) $\mathrm{KMnO}_{4}$
(c) $\mathrm{K}{2} \mathrm{Cr}{2} \mathrm{O}_{7}$
(d) None of these
Objective Questions II
(One or more than one correct option)
Show Answer
Solution:
- Fluorine, being the most electronegative, its size is very small. Therefore, it does not have a tendency to loose electrons. Hence, HF does not act as a reducing agent.
