pBlock ElementsII 1 Question 9
9. The order of the oxidation state of the phosphorus atom in $\mathrm{H}{3} \mathrm{PO}{2}, \mathrm{H}{3} \mathrm{PO}{4}, \mathrm{H}{3} \mathrm{PO}{3}$ and $\mathrm{H}{4} \mathrm{P}{2} \mathrm{O}_{6}$ is
(2017 Adv.)
(a) $\mathrm{H}{3} \mathrm{PO}{4}>\mathrm{H}{3} \mathrm{PO}{2}>\mathrm{H}{3} \mathrm{PO}{3}>\mathrm{H}{4} \mathrm{P}{2} \mathrm{O}_{6}$
(b) $\mathrm{H}{3} \mathrm{PO}{4}>\mathrm{H}{4} \mathrm{P}{2} \mathrm{O}{6}>\mathrm{H}{3} \mathrm{PO}{3}>\mathrm{H}{3} \mathrm{PO}_{2}$
(c) $\mathrm{H}{3} \mathrm{PO}{2}>\mathrm{H}{3} \mathrm{PO}{3}>\mathrm{H}{4} \mathrm{P}{2} \mathrm{O}{6}>\mathrm{H}{3} \mathrm{PO}_{4}$
(d) $\mathrm{H}{3} \mathrm{PO}{3}>\mathrm{H}{3} \mathrm{PO}{2}>\mathrm{H}{3} \mathrm{PO}{4}>\mathrm{H}{4} \mathrm{P}{2} \mathrm{O}_{6}$
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Solution:
- $\mathrm{H}{3} \stackrel{+5}{\mathrm{P}} \mathrm{O}{4}>\mathrm{H}{4} \stackrel{+4}{\mathrm{P}{2}} \mathrm{O}{6}>\mathrm{H}{3} \stackrel{+3}{\mathrm{P}} \mathrm{O}{3}>\mathrm{H}{3} \stackrel{+1}{\mathrm{P}} \mathrm{O}_{2}$
