pBlock ElementsII 1 Question 76
71. Among the following, the number of compounds that can react with $\mathrm{PCl}{5}$ to give $\mathrm{POCl}{3}$ is $\mathrm{O}{2}, \mathrm{CO}{2}, \mathrm{SO}{2}, \mathrm{H}{2} \mathrm{O}$, $\mathrm{H}{2} \mathrm{SO}{4}, \mathrm{P}{4} \mathrm{O}{10}$.
(2011)
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Solution:
- $\mathrm{PCl}{5}$ produces $\mathrm{POCl}{3}$ with the following reagents
$$ \begin{aligned} \mathrm{PCl}{5}+\mathrm{SO}{2} & \longrightarrow \mathrm{POCl}{3}+\mathrm{SOCl}{2} \ \mathrm{PCl}{5}+\mathrm{H}{2} \mathrm{O} & \longrightarrow \mathrm{POCl}{3}+2 \mathrm{HCl} \ 2 \mathrm{PCl}{5}+\mathrm{H}{2} \mathrm{SO}{4} & \longrightarrow \mathrm{SO}{2} \mathrm{Cl}{2}+2 \mathrm{POCl}{3}+2 \mathrm{HCl} \ 6 \mathrm{PCl}{5}+\mathrm{P}{4} \mathrm{O}{10} & \longrightarrow 10 \mathrm{POCl}_{3} \end{aligned} $$
