pBlock ElementsII 1 Question 30
30. Amongst $\mathrm{H}{2} \mathrm{O}, \mathrm{H}{2} \mathrm{~S}, \mathrm{H}{2} \mathrm{Se}$ and $\mathrm{H}{2} \mathrm{Te}$, the one with the highest boiling point is
(2000, 1M)
(a) $\mathrm{H}_{2} \mathrm{O}$ because of hydrogen bonding
(b) $\mathrm{H}_{2} \mathrm{Te}$ because of higher molecular weight
(c) $\mathrm{H}_{2} \mathrm{Sbecause}$ of hydrogen bonding
(d) $\mathrm{H}_{2} \mathrm{Se}$ because of lower molecular weight
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Solution:
- $\mathrm{H}_{2} \mathrm{O}$, due to its ability to form intermolecular H-bonds.
