Electrochemistry 2 Question 33
32. $2 \mathrm{Ag}^{+}+\mathrm{C}{6} \mathrm{H}{12} \mathrm{O}{6}+\mathrm{H}{2} \mathrm{O} \longrightarrow 2 \mathrm{Ag}(s)+\mathrm{C}{6} \mathrm{H}{12} \mathrm{O}_{7}+2 \mathrm{H}^{+}$
Find $\ln K$ of this reaction.
(a) 66.13
(b) 58.38
(c) 28.30
(d) 46.29
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Solution:
- $E^{\circ}$ for $2 \mathrm{Ag}^{+}+\mathrm{C}{6} \mathrm{H}{12} \mathrm{O}{6}+\mathrm{H}{2} \mathrm{O} \rightleftharpoons 2 \mathrm{Ag}(s)$
$$ +\mathrm{C}{6} \mathrm{H}{12} \mathrm{O}_{7}+2 \mathrm{H}^{+} \text {is } 0.75 \mathrm{~V} $$
Also $\quad E^{\circ}=\frac{0.0592}{2} \log K \Rightarrow \log K=\frac{2 E^{\circ}}{0.0592}=25.33$
$\Rightarrow \ln K=2.303 \log K=58.35$
