Electrochemistry 2 Question 17
16. An aqueous solution of $X$ is added slowly to an aqueous solution of $Y$ as shown in Column I. The variation in conductivity of these reactions is given in Column II. Match Column I with Column II and select the correct answer using the codes given below the Columns.
(2013 Adv.)
Codes
| $\mathrm{P}$ | $\mathrm{Q}$ | $\mathrm{R}$ | $\mathrm{S}$ | $\mathrm{P}$ | $\mathrm{Q}$ | $\mathrm{R}$ | $\mathrm{S}$ | ||
|---|---|---|---|---|---|---|---|---|---|
| (a) | 3 | 4 | 2 | 1 | (b) | 4 | 3 | 2 | 1 |
| (c) | 2 | 3 | 4 | 1 | (d) | 1 | 4 | 3 | 2 |
Show Answer
Solution:
- The variation is conductivities in general can be seen as :
III. \begin{tabular}{cc}
Weak
$\left(\mathrm{CH}_{3} \mathrm{COOH}\right)$
$\quad$
Strong
$(\mathrm{KOH})$
\end{tabular}
Conductivity decreases due to neutralisation of conducting strong base and then remains constant due to addition of weak acid.
to strong base
| In burette acid |
In flask base | Curve | |
|---|---|---|---|
| IV. | Weak $\left[\left(\mathrm{C}{2} \mathrm{H}{5}\right)_{3} \mathrm{~N}\right]$ |
Weak $\left(\mathrm{CH}_{3} \mathrm{COOH}\right)$ |
Conductivity increases due to formation of ions and then remains constant due to addition of weak base. |
| $\mathrm{V}$. | $\mathrm{K} X$ | $\mathrm{AgNO}_{3}$ | Insoluble salt $\mathrm{Ag} X$ is formed, hence conductance remains constant. It increases due to addition of $\mathrm{K} X$. |
