Electrochemistry 1 Question 31
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30. If the cathode is a $\mathrm{Hg}$ electrode, the maximum weight (in gram) of amalgam formed from this solution is
======= ####30. If the cathode is a $\mathrm{Hg}$ electrode, the maximum weight (in gram) of amalgam formed from this solution is
3e0f7ab6f6a50373c3f2dbda6ca2533482a77bed (a) 200
(b) 225
(c) 400
(d) 446
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Solution:
- At cathode $\mathrm{Na}^{+}+e^{-} \xrightarrow{\mathrm{Hg}} \underset{\text { Amalgam }}{\mathrm{Na}(\mathrm{Hg})}$
Two moles of $\mathrm{Na}$ formed during electrolysis would produce two moles of $\mathrm{Na}(\mathrm{Hg})$ amalgam.
$\Rightarrow$ mass of amalgam $=2 \times(23+200)=446 \mathrm{~g}$
