Electrochemistry 1 Question 11
11. Given, $E_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^{\circ}=-0.74 \mathrm{~V} ; E_{\mathrm{MnO}_{4}^{-} / \mathrm{Mn}^{2+}}^{\circ}=1.51 \mathrm{~V}$
Based on the data given above strongest oxidising agent will be
(2013 Main)
(a) $\mathrm{Cl}$
(b) $\mathrm{Cr}^{3+}$
(c) $\mathrm{Mn}^{2+}$
(d) $\mathrm{MnO}_{4}^{-}$
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Answer:
Correct Answer: 11. (d)
Solution:
- Higher the standard reduction potential, better is oxidising agent. Among the given $E_{\mathrm{MnO}{4}^{-} / \mathrm{Mn}^{2+}}^{\circ}$ is highest, hence $\mathrm{MnO}{4}^{-}$is the strongest oxidising agent.
